UPSC CSE Prelims 2025
Let the two natural numbers be $n_1$ and $n_2$, such that $n_2 - n_1 = 10$. We are interested in the count of natural numbers divisible by 5 that lie strictly between $n_1$ and $n_2$. These numbers are $n_1+1, n_1+2, \dots, n_2-1$. This sequence comprises 9 consecutive natural numbers.
Consider the following cases:
Let $n_1 = 5k$ for some natural number $k$. Then $n_2 = 5k + 10$. The numbers strictly between $n_1$ and $n_2$ are $5k+1, 5k+2, \dots, 5k+9$. In this sequence, only $5k+5$ is a multiple of 5. For example, if $n_1=5$ and $n_2=15$, the numbers between them are $6, 7, \dots, 14$. Only $10$ is divisible by 5, which is one number.
Let $n_1 = 5k+r$, where $r \in \{1, 2, 3, 4\}$. Then $n_2 = 5k+r+10$. The numbers strictly between $n_1$ and $n_2$ are $5k+r+1, \dots, 5k+r+9$. Within any sequence of 9 consecutive natural numbers, if the sequence does not start or end with a multiple of 5, it will contain two multiples of 5.
Since there are instances where two such numbers exist, it is possible for there to be more than one number divisible by 5 between the two given natural numbers.
Options (1), (2), and (4) are incorrect because the number of natural numbers divisible by 5 between the two given numbers is not constant. As demonstrated, there are scenarios where only one such number exists (e.g., between 5 and 15) and scenarios where two such numbers exist (e.g., between 1 and 11). Therefore, stating there is always only one, always only two, or never any such number is inaccurate.