UPSC CSE Prelims 2021
The problem requires determining the number of distinct combinations to select 3 persons from a row of 6, such that no two selected persons are consecutive.
First, calculate the total number of ways to choose 3 persons from 6 without any restrictions. This is determined using the combination formula:
Next, identify and subtract the combinations where at least two selected persons are consecutive. These can be categorized into two cases:
Case 1: All three chosen persons are consecutive.
There are 4 such combinations.
Case 2: Exactly two chosen persons are consecutive.
This implies two persons form a consecutive pair, and the third person is not adjacent to either of them.
The total number of combinations where exactly two persons are consecutive is 3 + 2 + 2 + 2 + 3 = 12.
The total number of restricted combinations (where at least two persons are consecutive) = (Case 1) + (Case 2) = 4 + 12 = 16.
Therefore, the number of distinct possible combinations where no two persons are consecutive is calculated by subtracting the restricted combinations from the total combinations:
20 - 16 = 4.
The final answer is 4.
Options A (3), C (5), and D (6) are incorrect. These values do not correspond to the precise calculation, which systematically accounts for all possible combinations and excludes those where selected persons are consecutive.