A train 200 metres long is moving at the rate of 40 kmph. In how many seconds will it cross a man standing near the railway line?

Correct Option (4)

To calculate the time required for a train to cross a stationary object, such as a man, the distance covered by the train is equal to its own length. The given parameters are:

• Length of the train (Distance) = 200 meters
• Speed of the train = 40 kmph

For consistent units, the speed must be converted from kilometers per hour (kmph) to meters per second (m/s):

Speed = 40 kmph × (5/18) m/s = (200/18) m/s = (100/9) m/s

Now, apply the formula for time:

Time = Distance / Speed

Time = 200 meters / ((100/9) m/s)

Time = 200 × (9/100) seconds

Time = 2 × 9 seconds

Time = 18 seconds

Thus, the train will cross the man in 18 seconds.

Incorrect Options:

Options (1) 12, (2) 15, and (3) 16 are incorrect. These values do not result from the accurate application of the distance, speed, and time relationship, considering the given train length and speed, and after performing the necessary unit conversions.