UPSC CSE Prelims 2013
Given that B is selected and Y is rejected. According to the problem statement, B cannot play with W. Therefore, if B is selected, W must be rejected from the team.
The available players are A, B, C (males) and W, X, Y, Z (females).
Based on the conditions:
The players remaining for selection are A, C (males) and X, Z (females). We need to select 3 more players to form a team of four.
The team must have at least two males. Since B is already selected, we need to select at least one more male from A or C.
Let us consider selecting both remaining males, A and C. This forms a core of three males (A, B, C), satisfying the "at least two males" condition.
Now, one more player is needed from the remaining females (X, Z).
The problem states that C cannot play with Z. Since C is part of our selected core (A, B, C), Z cannot be selected as the fourth player.
Therefore, the only eligible female remaining is X.
The resulting team is A, B, C, X.
This team satisfies all conditions:
The initial conditions are: B is selected, Y is rejected.
Option (A) A, B, C and W:
Option (B) A, B, C and Z:
Option (D) A, W, Y and Z: